Question 1

All aldoses and ketoses are reducing sugars.

Accepted Answer

A) True 
 B)False

Question 2

Modern glucose meters are electronic devices that measure the amount of oxidizing agent that reacts with the glucose in a known amount of blood.

Accepted Answer

A) True 
 B)False  True

Question 3

Dextrose is another name for the monosaccharide _____.

Accepted Answer

The answer of Dextrose is another name for the monosaccharide...

Question 4

The carbonyl group of an aldose is reduced to a secondary alcohol using hydrogen (H2)in the presence of palladium (Pd)metal.

Accepted Answer

A) True 
 B)False

Question 5

Which labeled carbon atom in the structure below is the anomeric carbon?

Accepted Answer

A)  A
B)  B
C)  C
D)  DE) B) and C)
F) A) and C)

Question 6

Certain monosaccharides-notably aldopentoses and ketohexoses-form five-membered rings, not six-membered rings, in solution.

Accepted Answer

A) True 
 B)False

Question 7

What product forms when the compound below is treated with Benedict's reagent?

Accepted Answer

A)   
B)   
C)   
D)   
E)  No reaction occurs.F) A) and C)
G) A) and D)

Question 8

The structure shown has four (4)chirality centers and is a D monosaccharide.

Accepted Answer

A) True 
 B)False

Question 9

In aldohexoses, it is the -OH group on C5 that reacts with the aldehyde carbonyl to form two cyclic hemiacetals called anomers.

Accepted Answer

A) True 
 B)False

Question 10

Why are humans not able to digest cellulose?

Accepted Answer

A)  Humans cannot digest glucose.
B)  Humans do not possess the enzyme necessary to hydrolyze the 1 →\rightarrow→ 4- β\betaβ -glycoside linkages found in cellulose.
C)  Humans do not possess the enzyme necessary to unwind the helical shape of the cellulose molecule.
D)  Humans do not possess the enzyme necessary to hydrolyze the 1 →\rightarrow→ 4- α\alphaα -glycoside linkages found in cellulose. E) A) and B)
F) None of the above B

Question 11

Monosaccharides with a carbonyl group at C2 are called ketoses.

Accepted Answer

A) True 
 B)False

Question 12

Dihydroxyacetone, shown below, is the simplest ketose. Does the structure shown represent D-dihydroxyacetone or L-dihydroxyacetone?

Accepted Answer

A)  D-dihydroxyacetone
B)  L-dihydroxyacetone
C)  Neither D nor L; dihydroxyacetone is not chiral
D)  It is impossible to tell from the Fischer projection alone.E) None of the above
F) A) and D)

Question 13

In addition to the three monosaccharides that occur in all blood types, type A blood contains the monosaccharide N-acetyl-D-galactosamine, and type B blood contains an additional D-galactose unit.

Accepted Answer

A) True 
 B)False

Question 14

What is the classification of the compound shown below?

Accepted Answer

A)  a tetraketose
B)  a ketotriose
C)  a ketotetrose
D)  an aldotrioseE) B) and C)
F) C) and D)

Question 15

Which carbohydrates cannot be converted to simpler compounds by hydrolysis?

Accepted Answer

A)  disaccharides
B)  monosaccharides
C)  polysaccharides
D)  starchesE) A) and D)
F) A) and C)

Question 16

When converting a Fischer projection to a Haworth projection, where are all of the substituents on the right side of the carbon skeleton drawn in the Haworth projection?

Accepted Answer

A)  down
B)  up
C)  down in an  α\alphaα  anomer and up in a  β\betaβ  anomer
D)  down in an  β\betaβ  anomer and up in a  α\alphaα anomer E) B) and C)
F) B) and D)

Question 17

When a monosaccharide forms a cyclic hemiacetal, the carbon atom that is part of the hemiacetal is a new chirality center, called the anomeric carbon.

Accepted Answer

A) True 
 B)False

Question 18

Salicin is a naturally occurring, carbohydrate-containing pain reliever. Which statement concerning the functional groups present in salicin is incorrect?

Accepted Answer

A)  Salicin contains an acetal.
B)  Salicin contains an alcohol.
C)  Salicin contains a hemiacetal.
D)  Salicin contains a phenol.E) C) and D)
F) All of the above

Question 19

Individuals with type AB blood are called universal recipients because their blood contains no antibodies to blood types A, B, or O. Individuals with type AB blood can receive blood of any type.

Accepted Answer

A) True 
 B)False

Question 20

Which naturally-occurring monosaccharide forms the Haworth structure shown?

Accepted Answer

A)   
B)   
C)   
D)   E) C) and D)
F) B) and D) B

Exam 20: Carbohydrates

All aldoses and ketoses are reducing sugars.

Correct AnswerverifiedShow Answer

Modern glucose meters are electronic devices that measure the amount of oxidizing agent that reacts with the glucose in a known amount of blood.

Correct AnswerverifiedTrue

Dextrose is another name for the monosaccharide _____.

Correct AnswerverifiedShow Answer

The carbonyl group of an aldose is reduced to a secondary alcohol using hydrogen (H2)in the presence of palladium (Pd)metal.

Correct AnswerverifiedShow Answer

Which labeled carbon atom in the structure below is the anomeric carbon?

Correct AnswerverifiedShow Answer

Certain monosaccharides-notably aldopentoses and ketohexoses-form five-membered rings, not six-membered rings, in solution.

Correct AnswerverifiedShow Answer

What product forms when the compound below is treated with Benedict's reagent?

Correct AnswerverifiedShow Answer

The structure shown has four (4)chirality centers and is a D monosaccharide.

Correct AnswerverifiedShow Answer

In aldohexoses, it is the -OH group on C5 that reacts with the aldehyde carbonyl to form two cyclic hemiacetals called anomers.

Correct AnswerverifiedShow Answer

Why are humans not able to digest cellulose?

Correct AnswerverifiedB

Monosaccharides with a carbonyl group at C2 are called ketoses.

Correct AnswerverifiedShow Answer

Dihydroxyacetone, shown below, is the simplest ketose. Does the structure shown represent D-dihydroxyacetone or L-dihydroxyacetone?

Correct AnswerverifiedShow Answer

In addition to the three monosaccharides that occur in all blood types, type A blood contains the monosaccharide N-acetyl-D-galactosamine, and type B blood contains an additional D-galactose unit.

Correct AnswerverifiedShow Answer

What is the classification of the compound shown below?

Correct AnswerverifiedShow Answer

Which carbohydrates cannot be converted to simpler compounds by hydrolysis?

Correct AnswerverifiedShow Answer

When converting a Fischer projection to a Haworth projection, where are all of the substituents on the right side of the carbon skeleton drawn in the Haworth projection?

Correct AnswerverifiedShow Answer

When a monosaccharide forms a cyclic hemiacetal, the carbon atom that is part of the hemiacetal is a new chirality center, called the anomeric carbon.

Correct AnswerverifiedShow Answer

Salicin is a naturally occurring, carbohydrate-containing pain reliever. Which statement concerning the functional groups present in salicin is incorrect?

Correct AnswerverifiedShow Answer

Individuals with type AB blood are called universal recipients because their blood contains no antibodies to blood types A, B, or O. Individuals with type AB blood can receive blood of any type.

Correct AnswerverifiedShow Answer

Which naturally-occurring monosaccharide forms the Haworth structure shown?

Correct AnswerverifiedB

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True

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The carbonyl group of an aldose is reduced to a secondary alcohol using hydrogen (H₂)in the presence of palladium (Pd)metal.

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B

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B